Author: Stan Eisenstat
Subject: Re: [Cs323] None
Date: Monday, 21 Sep 2020, 22:21:59
> Message Posted By: Anonymous > > Can we assume that tokens will be broken up by characters that return true > for isspace()? No. ===== > In the spec I see the example: > < A B | ( C 2> D & E < F ) > G ; H=I J K > There is a space between the ( and C and another between F and ). If we > see (C, or F) - without spaces - would (C count as one token, or do we > have to catch this and split them up into ( and C as separate tokens? The latter, as you can verify by running Hwk2/parsley. --Stan-PREV INDEX NEXT