Author: Stan Eisenstat
Subject: Re: [Cs323] None
Date: Monday, 21 Sep 2020, 22:21:59

    > Message Posted By: Anonymous
    >
    > Can we assume that tokens will be broken up by characters that return true
    > for isspace()?

No.
=====
    > In the spec I see the example:
    > < A B | ( C 2> D & E < F ) > G ; H=I J K
    > There is a space between the ( and C and another between F and ). If we
    > see (C, or F) - without spaces - would (C count as one token, or do we
    > have to catch this and split them up into ( and C as separate tokens?

The latter, as you can verify by running Hwk2/parsley.

--Stan-